| Theory |
A coil is fitted with series taps such that each tap can be closed by a link, or by a small resistance, as shown below.

In this example the coil winding is broken into ten roughly equal sections, giving eleven tapping points numbered 0..10 from the base. A resistance is inserted into each tap, one at a time, and the resulting Q measured for each of the eleven taps. An additional Q measurement is taken with no resistance inserted. The current profile can then be calculated from the resulting set of twelve Q measurements.
This method does not require knowledge of the resistor value, or the resonant frequencies. No voltage or current measurements are required. The calculation proceeds as follows: For the ringdown, for each frequency component,
Eloss/Es = 2 pi / Qwhere Eloss is energy lost per cycle and Es is the stored energy, (both functions of time). Consider Eloss to be the sum of the energy lost in the coil (Ec) plus the energy lost in the extra series resistance (Ex). Then we can say
Ec/Es = 2*pi/Qs ...(1)where Qs is the Q measured without the extra resistor. With the resistor added at point x = 0..10 in the coil, we have
(Ec + Ex)/Es = 2*pi/Qx ...(2)where Qx is the associated observed Q. We have 11 of these equations. Substituting (1) into (2) gives
Ex/Es = 2*pi/(1/Qx - 1/Qs) ...(3)Now at any cycle of the ringdown,
Es = Lee * Ib^2/2where Ib is the peak base current, and the 11 equations
Ex = R * Ix^2/(2*f) x = 0..10in which Ix is the peak current at the resistor point x, With these, (3) becomes
Ix^2/Ib^2 = 2*pi*f*Lee/R * (1/Qx - 1/Qs)which is independent of time now that we have eliminated all the energy terms. Noting that Ib = Ix when x = 0, we have
1 = 2*pi*f*Lee/R * (1/Q0 - 1/Qs)and the other ten equations
Ix^2/Ib^2 = 2*pi*f*Lee/R * (1/Qx - 1/Qs) ; x = 2..10The first equation gives
2*pi*f*Lee/R = Q1 * Qs/(Qs - Q0)and using this to eliminate all the unknowns in the remaining ten equations gives
Ix^2/Ib^2 = (1/Qx - 1/Qs) * Q0 * Qs/(Qs - Q0) ; x = 1..10Therefore eleven Q measurements Q0 to Q10, one for each link, plus an extra one Qs of the coil without the resistor, can be used to determine the current profile Ix/Ib through the formula
Ix/Ib = 1 ; x = 0
Ix/Ib = sqrt{ (Qs - Qx)/(Qs - Q0) * Q0/Qx } ; x = 1..10
It can be seen from the above equation that the resulting current profiles are quite sensitive to the difference between measured Q values.
Therefore, for this method to be successful, high precision Q measurements are necessary.
| Experiment |
and
(b) To confirm the predicted current profile for the coil, and to demonstrate the elevated current maximum in a resonating solenoid, as shown in fig 6.1 of pn2511.
Measured Modeled Error
f1/4 229.9 kHz 229.3 kHz -0.3%
f3/4 578.1 kHz 570.4 kHz -1.3%
f5/4 904.1 kHz 908.9 kHz +0.5%
Ldc 39.0 mH 39.18 mH +0.5%
Rdc 32.65 ohms 32.91 ohms +0.8%
The modeling program is making a rough compensation for the coil former dielectric in the above figures. The frequency match is
good on the first three resonant modes, which is enough to indicate that the model is correctly set up.
Therefore we expect a good match on the current profiles.
Turn Measurement Q1/4 Ix/Ib Q3/4 Ix/Ib Q5/4 Ix/Ib
0 Q0 TEK00001 283.73 1.000 167.37 1.000 102.28 1.000
43 Q1 TEK00002 234.04 1.243 134.53 1.907 87.25 2.308
87 Q2 TEK00003 219.97 1.320 135.33 1.886 98.32 1.418
135 Q3 TEK00004 215.22 1.347 152.51 1.432 105.97 0.354
179 Q4 TEK00005 216.63 1.339 176.59 0.661 91.38 1.999
222 Q5 TEK00006 225.62 1.288 182.10 0.356 83.81 2.557
265 Q6 TEK00007 242.45 1.198 161.33 1.185 94.60 1.743
309 Q7 TEK00008 268.92 1.068 138.21 1.810 105.66 0.443
354 Q8 TEK00009 309.45 0.887 129.02 2.051 95.48 1.670
398 Q9 TEK00010 366.75 0.648 141.24 1.731 87.35 2.301
442 Q10 TEK00011 464.28 0.060 184.04 0.149 107.05 0.000
along with the unloaded reading
Qs TEK00000 465.35 184.46 106.52
The detailed tcma output results from which these results are summarised, can be seen
in tcma-output.txt. Raw data CSV files, and pictures of the
experiment can be seen
here. The measurement run only took a few
minutes, so we make no attempt to compensate for the negligible temperature variation.
1/4 wave
3/4 wave
We see good agreement on the 1/4 wave mode, and a reasonably good match with the 3/4 wave.
The 5/4 wave mode below is showing some significant errors, of up to 10%.
5/4 wave
Note: The ripple effect on the predicted current profiles is an artifact of the coil modeling software. It is caused by the interpolation method which deals with the limited spatial resolution of the internal capacitance. The particular method used has good global accuracy at the expense of some local aliasing noise, which appears as the ripple. This turns out to be quite convenient in practice, because you can see at a glance those parts of the current profile which are being strongly affected by internal capacitance.
| Conclusions |
The experiment also gives us a clear demonstration that the ratio Les/Ldc can exceed unity, in this case by around 12%.
We can also extract a direct measurement of the equivalent energy storage inductance, Lee from the results as follows: If Rin is the input resistance at resonance, and R is the added series resistance, we have
Rin = 2 pi F Lee/Qsand
Rin + R = 2 pi F Lee/Q0Rearranging these and substituting to eliminate the unknown Rin, we obtain
Lee = Q0 Qs R / (Qs - Q0) / (2 pi F)Using the measured values of R, Q0, Qs, and F, we get
F R Q0 Qs Lee Meas Lee Model Error
f1/4 229900 100.57 283.73 465.35 50.6 mH 50.87 mH +0.5%
f3/4 578100 100.57 167.37 184.46 50.0 mH 49.98 mH 0.0%
f5/4 904100 100.57 102.28 106.52 45.5 mH 39.95 mH -12.2%
which confirms the predicted values of Lee at f1/4 and f3/4.
The error at f5/4 is due to the closeness of the two Q readings, each of which is subject to a few percent error. An accurate value
for Lee at this resonance would require re-measuring with a higher value of series resistance.
This experiment provides strong evidence that the modeling process is correctly quantifying the internal capacitance of the coil, and that this capacitance is being properly applied in the solenoid model.